Assuming that b > 0, it is an inverse power function or an inverse exponential function.
Greater than 0
That means that either the function is equal to zero everywhere (y = 0), or it is the exponential function (y = ex).
Yes....0.9 is greater than 0. 0.9 > 0
Yes 0 is greater than -22
"The base of the exponent" doesn't make sense; base and exponent are two different parts of an exponential function. To be an exponential function, the variable must be in the exponent. Assuming the base is positive:* If the base is greater than 1, the function increases. * If the base is 1, you have a constant function. * If the base is less than 1, the function decreases.
If the first derivative of a function is greater than 0 on an interval, then the function is increasing on that interval. If the first derivative of a function is less than 0 on an interval, then the function is decreasing on that interval. If the second derivative of a function is greater than 0 on an interval, then the function is concave up on that interval. If the second derivative of a function is less than 0 on an interval, then the function is concave down on that interval.
f(x) = (x)^ (1/2) (i.e. the square root of x)
Yes it can.
Assuming that b > 0, it is an inverse power function or an inverse exponential function.
Greater than 0
You find out if a problem is linear or exponential by looking at the degree or the highest power; if the degree or the highest power is 1 or 0, the equation is linear. But if the degree is higher than 1 or lower than 0, the equation is exponential.
That means that either the function is equal to zero everywhere (y = 0), or it is the exponential function (y = ex).
Yes....0.9 is greater than 0. 0.9 > 0
Yes 0 is greater than -22
y is greater than 0
This question appears to relate to some problem for which we have no information. The graph of an exponential function shows a doubling at regular intervals. But we are not told what the role is of b, so we cannot comment further.