In an exponential function of the form ( f(x) = b^x ), where ( b ) is the base, ( b ) must be greater than 0 to ensure that the function is defined for all real numbers ( x ). If ( b ) were less than or equal to 0, the function would either be undefined (as in the case of negative bases for non-integer exponents) or not exhibit the characteristic growth behavior of exponential functions. Additionally, a positive base guarantees that the function remains continuous and either increases (for ( b > 1 )) or decreases (for ( 0 < b < 1 )), maintaining its fundamental properties.
The base of 1 is not used for exponential functions because it does not produce varied growth rates. An exponential function with a base of 1 would result in a constant value (1), regardless of the exponent, failing to demonstrate the characteristic rapid growth or decay associated with true exponential behavior. Therefore, bases greater than 1 (for growth) or between 0 and 1 (for decay) are required to reflect the dynamic nature of exponential functions.
Greater than 0
Assuming that b > 0, it is an inverse power function or an inverse exponential function.
That means that either the function is equal to zero everywhere (y = 0), or it is the exponential function (y = ex).
Yes....0.9 is greater than 0. 0.9 > 0
"The base of the exponent" doesn't make sense; base and exponent are two different parts of an exponential function. To be an exponential function, the variable must be in the exponent. Assuming the base is positive:* If the base is greater than 1, the function increases. * If the base is 1, you have a constant function. * If the base is less than 1, the function decreases.
To determine if an equation represents exponential growth or decay, look at the base of the exponential function. If the base is greater than 1 (e.g., (y = a \cdot b^x) with (b > 1)), the function represents exponential growth. Conversely, if the base is between 0 and 1 (e.g., (y = a \cdot b^x) with (0 < b < 1)), the function indicates exponential decay. Additionally, the sign of the exponent can also provide insight into the behavior of the function.
If the first derivative of a function is greater than 0 on an interval, then the function is increasing on that interval. If the first derivative of a function is less than 0 on an interval, then the function is decreasing on that interval. If the second derivative of a function is greater than 0 on an interval, then the function is concave up on that interval. If the second derivative of a function is less than 0 on an interval, then the function is concave down on that interval.
f(x) = (x)^ (1/2) (i.e. the square root of x)
Yes it can.
Greater than 0
Assuming that b > 0, it is an inverse power function or an inverse exponential function.
You find out if a problem is linear or exponential by looking at the degree or the highest power; if the degree or the highest power is 1 or 0, the equation is linear. But if the degree is higher than 1 or lower than 0, the equation is exponential.
That means that either the function is equal to zero everywhere (y = 0), or it is the exponential function (y = ex).
Yes....0.9 is greater than 0. 0.9 > 0
y is greater than 0
This question appears to relate to some problem for which we have no information. The graph of an exponential function shows a doubling at regular intervals. But we are not told what the role is of b, so we cannot comment further.