A sum of 4 is more likely. Out of the 36 possible outcomes with a pair of 6-sided dice, only one will have a sum of 2 {1-1}. Three of the possibilities sum to 4. {1-3, 2-2, 3-1}
The sum of 3 plus 4 is 7.
The number is 4 (4+3) * (4+3) = 49 (4+2) * (4+2) = 36 49 - 36 = 13
0.75
The product of 4 and 3 is (4 \times 3 = 12). The sum of 4 and 3 is (4 + 3 = 7). To find how much greater the product is than the sum, we subtract the sum from the product: (12 - 7 = 5). Therefore, the product is 5 greater than the sum.
A sum of 4 is more likely. Out of the 36 possible outcomes with a pair of 6-sided dice, only one will have a sum of 2 {1-1}. Three of the possibilities sum to 4. {1-3, 2-2, 3-1}
The sum of 3 plus 4 is 7.
The number is 4 (4+3) * (4+3) = 49 (4+2) * (4+2) = 36 49 - 36 = 13
0.75
The product of 4 and 3 is (4 \times 3 = 12). The sum of 4 and 3 is (4 + 3 = 7). To find how much greater the product is than the sum, we subtract the sum from the product: (12 - 7 = 5). Therefore, the product is 5 greater than the sum.
4
4
4 and -1 have a product of -4 and a sum of 3.
4/3.
75 - 4% = 72, so therefore 4% of 75 is 3
-2
What is the sum of greatest 3-digit 4-digit 5digit