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assuming that the pipes are all the same length, then you can work it out as follows: The pipes are cylindrical, and the volume of a cylinder is equal to pi multiplied by the square of it's radius multiplied by the length of the pipe - or: v = πr2h we can compare the two then by saying the volume of our two smaller pipes is: v = πr12h + πr22h r1 = 3 and r2 = 4, therefore v = π32h + π42h v = π9h + π16h v = π25h and then we can say that the volume of our biggest pipe is: v = πr2h r = 5, therefore v = π52h v = π25h therefore, the two small pipes carry the same amount as the large pipe
To start, we will find the cross sectional area of the pipes. Pipe with radius of 2 inches Cross sectional area = PI x radius2 = 12.56 inches2 Pipe with radius of 3 inches Cross sectional area = PI x radius2 = 28.26 inches2 Pipe with radius of 5 inches Cross sectional area = PI x radius2 = 78.5 inches2 As the cross sectional area of the pipe with a radius of 5 inches (78.5 inches2) is greater than the sum of the cross sectional areas of the pipes with radii of 2 inches and 3 inches (40.82 inches2), it can be concluded that the pipe with a radius of 5 inches will be able to carry the most water. (Assuming that all three pipes are the same length).
They both have the same effect on the surface area of the pipe, but the radius has more effect on its volume/capacity.
Its capacity or volume - measured in the same units.Its capacity or volume - measured in the same units.Its capacity or volume - measured in the same units.Its capacity or volume - measured in the same units.
Yes, volume is the same as capacity. For instance, a pint pot can hold a pint, and so its capacity is a pint, or it will overflow.