I think it would be a negative answer because if you do it that many times and it is odd number it is most likely to be a negative answer than a positive answer. If you multiply a negative by another negative an even number of times, it will be even, but if it is done an odd number of times, like in your example, the result will be an odd number.
Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd. ========================== You've just read a truly impressive answer to a question slightly different from the one that was asked. The part of the question that comes after "Why if ..." is a false statement. If you multiply odd number with another number, the result is odd number ONLY if the nother number is also odd number.
When you multiply an odd number by an even number, you are essentially adding an even number of odd numbers together. Since adding an even number of odd numbers will always result in an even number, the product will be even.
When you add them, you always get an even number; when you multiply them, the result is always odd.
An even number.
I think it would be a negative answer because if you do it that many times and it is odd number it is most likely to be a negative answer than a positive answer. If you multiply a negative by another negative an even number of times, it will be even, but if it is done an odd number of times, like in your example, the result will be an odd number.
Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd. ========================== You've just read a truly impressive answer to a question slightly different from the one that was asked. The part of the question that comes after "Why if ..." is a false statement. If you multiply odd number with another number, the result is odd number ONLY if the nother number is also odd number.
you would get an even number; 2x1=2 2x3=6 2x5=10
Odd times even is even.
yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
if you multiply an even number by 5 then it will always end in 0 but if you multiply an odd number by 5 then it will always end in 5.
the result is always even
When you multiply an odd number by an even number, you are essentially adding an even number of odd numbers together. Since adding an even number of odd numbers will always result in an even number, the product will be even.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Odd times even is even.
If you multiply any even number by an even number, the product is an even number.
because when mulitipling that number your always going to get a greater number because that's just how mulipication worksWhen multiplying two whole numbers the result will always be greater than either number except when multiplying by zero (the result will always be zero), or multiplying by one (the result is always the other number). Although it f obvious to most people, it can be demonstrated as follows:When multiplying a number by 2, the result is twice the number.When multiplying a number by 3, the result is three times the number,even bigger.When multiplying a number by 4, the result is four times the number,even bigger still.The pattern continues. Each time you multiply by a larger number, the result gets even bigger.a
Yes, assuming you're multiplying it by another integer. By definition, an even number is a multiple of two. When you multiply it be another round number, that even number becomes a factor of the result. That means any factors of that even number (one of them being two), will also be factors of the result, thus giving you another even number. If however you multiply by a non-integer, you may very well end up with something that is not an even number. For example, 6 is an even number, but 6 × 1.5 will give you 9, which is not an even number.