its always an even number....im pretty sure.
No, the product of an odd number and an even number is always even. This is because an even number can be expressed as a multiple of 2, and when you multiply it by any integer, the result will still be a multiple of 2, hence even.
I think it would be a negative answer because if you do it that many times and it is odd number it is most likely to be a negative answer than a positive answer. If you multiply a negative by another negative an even number of times, it will be even, but if it is done an odd number of times, like in your example, the result will be an odd number.
Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd. ========================== You've just read a truly impressive answer to a question slightly different from the one that was asked. The part of the question that comes after "Why if ..." is a false statement. If you multiply odd number with another number, the result is odd number ONLY if the nother number is also odd number.
In mathematics, an even number is defined as any integer that can be expressed as (2n), where (n) is an integer, while an odd number can be expressed as (2m + 1) for some integer (m). When you multiply an even number by any integer (even or odd), the result is still even, because the product will still have a factor of 2. Therefore, when you multiply an even number by an odd number, the product remains an even number. Thus, even times odd equals even.
When you multiply an odd number by an even number, you are essentially adding an even number of odd numbers together. Since adding an even number of odd numbers will always result in an even number, the product will be even.
No, the product of an odd number and an even number is always even. This is because an even number can be expressed as a multiple of 2, and when you multiply it by any integer, the result will still be a multiple of 2, hence even.
I think it would be a negative answer because if you do it that many times and it is odd number it is most likely to be a negative answer than a positive answer. If you multiply a negative by another negative an even number of times, it will be even, but if it is done an odd number of times, like in your example, the result will be an odd number.
Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd. ========================== You've just read a truly impressive answer to a question slightly different from the one that was asked. The part of the question that comes after "Why if ..." is a false statement. If you multiply odd number with another number, the result is odd number ONLY if the nother number is also odd number.
In mathematics, an even number is defined as any integer that can be expressed as (2n), where (n) is an integer, while an odd number can be expressed as (2m + 1) for some integer (m). When you multiply an even number by any integer (even or odd), the result is still even, because the product will still have a factor of 2. Therefore, when you multiply an even number by an odd number, the product remains an even number. Thus, even times odd equals even.
you would get an even number; 2x1=2 2x3=6 2x5=10
Odd times even is even.
yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
if you multiply an even number by 5 then it will always end in 0 but if you multiply an odd number by 5 then it will always end in 5.
the result is always even
When you multiply an odd number by an even number, you are essentially adding an even number of odd numbers together. Since adding an even number of odd numbers will always result in an even number, the product will be even.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Odd times even is even.
If you multiply any even number by an even number, the product is an even number.