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What makes the equation correct 13 equals y-2?
y = 15 so that 13= 15 - 2 y-2 = 13 y-2 +2 = 13 +2 y = 15
What is the equation containing (13) with a slope of -2?
If you mean: (1, 3) then its equation is y = -2x+5
What is the equation for a circle centered at the point (-13) and has a radius of length 4. What is the equation?
It is (x + 1)2 + (y - 3)2 = 42
What is the perpendicular bisector equation of the line joined by the points of 7 3 and -6 1?
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Equation: y-2 = -13/2(x-0.5) => 2y-4 = -13(x-0.5) => 2y = -13x+10.5 Perpendicular bisector equation in its general form: 13x+2y -10.5 = 0
How do you form an equation for the perpendicular bisector of the line AB when A is at the point of 7 3 and B is at the point of -6 1?
First find the midpoint of AB which is (1/2, 2) Then find the slope of AB which is 2/13 The slope of the perpendicular bisector is the negative reciprocal of 2/13 which is -13/2. Then by using the formula y-y1 = m(x-x1) form an equation for the perpendicular bisector which works out as:- y -2 = -13/2(x -1/2) y = -13/2x + 13/4 + 2 y = -13/2x + 21/4 So the equation is: 4y = -26x + 21
