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What is the equation of the line if the slope is 2 and containing 3 9?
Y=2x+3 (I'm 13 and I knew that
Which equation is best represented by a line containing the ponts 2 -5 and 4 3?
It is a straight line equation and its solution is worked out as follows:- Points: (2, -5) and (4, 3) Slope: (-5-3)/(2-4) = 4 Equation: y--5 = 4(x-2) => y = 4x-8-5 => y = 4x-13 Equation: y-3 = 4(x-4) => y = 4x-16+3 => y = 4x-13 So in slope-intercept form: y = 4x-13 whereas 4 is the slope and -13 is the y intercept
What is the equation of a line through the point (2 17) and has a slope of 7?
write an equation that has a slope 7 and passes through the point (2,17)
Determine the equation for each line slope 5 containing the point 3 2?
Let the equation of the line be y = mx + c The slope is 5 so m = 5 ie y = 5x + c The point (3,2) is on the line so substitute x = 3, y = 2 in this equation to give: 2 = 5*3 + c or 2=15+c Then subtract 15 off both sides as to calculate c. 2-15=-13 so that c = -13 Therefore the equation is y = 5x - 13
What is the slope of this equation y equals 3-2x?
5
What is the equation of the line if the slope is 2 and containing 3 9?
Y=2x+3 (I'm 13 and I knew that
Find the equation of the line containing the two points shown?
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
What is the perpendicular bisector equation in its general form that meets the line containing the points 7 3 and -6 1 showing work?
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular equation: y-2 = -13/2(x-0.5) => 2y = -13x+10.5 Perpendicular bisector equation in its general form: 26x+4y-21 = 0
Which equation is best represented by a line containing the ponts 2 -5 and 4 3?
It is a straight line equation and its solution is worked out as follows:- Points: (2, -5) and (4, 3) Slope: (-5-3)/(2-4) = 4 Equation: y--5 = 4(x-2) => y = 4x-8-5 => y = 4x-13 Equation: y-3 = 4(x-4) => y = 4x-16+3 => y = 4x-13 So in slope-intercept form: y = 4x-13 whereas 4 is the slope and -13 is the y intercept
What is the equation of a line through the point (2 17) and has a slope of 7?
write an equation that has a slope 7 and passes through the point (2,17)
Determine the equation for each line slope 5 containing the point 3 2?
Let the equation of the line be y = mx + c The slope is 5 so m = 5 ie y = 5x + c The point (3,2) is on the line so substitute x = 3, y = 2 in this equation to give: 2 = 5*3 + c or 2=15+c Then subtract 15 off both sides as to calculate c. 2-15=-13 so that c = -13 Therefore the equation is y = 5x - 13
Find an equation of the line having the given slope and containing the given point m equals 2 over 3 and 2 and -1?
If the slope is 2/3 and the coordinate is (2, -1) then the straight line equation is 3y=2x-7
What is the equation in slope intercept form of the line that has a slope of 2 and contains the point 3 7?
y=2x+13
What is the equation of the line whose coordinates are at 2 3 and 11 13?
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9x = 10x+7
What is the perpendicular bisector equation that meets the line of 7 3 and -6 1 on the Cartesian plane?
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular equation: y-2 = -13/2(x-0.5 => 2y = -13x+10.5
What is the slope of this equation y equals 3-2x?
5
What is the perpendicular bisector equation of the line joined by the points of 7 3 and -6 1?
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Equation: y-2 = -13/2(x-0.5) => 2y-4 = -13(x-0.5) => 2y = -13x+10.5 Perpendicular bisector equation in its general form: 13x+2y -10.5 = 0
