If you mean: (1, 3) then its equation is y = -2x+5
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Y=2x+3 (I'm 13 and I knew that
It is a straight line equation and its solution is worked out as follows:- Points: (2, -5) and (4, 3) Slope: (-5-3)/(2-4) = 4 Equation: y--5 = 4(x-2) => y = 4x-8-5 => y = 4x-13 Equation: y-3 = 4(x-4) => y = 4x-16+3 => y = 4x-13 So in slope-intercept form: y = 4x-13 whereas 4 is the slope and -13 is the y intercept
Point: (2, 17)Slope: 7Equation: y = 2x+13
Let the equation of the line be y = mx + c The slope is 5 so m = 5 ie y = 5x + c The point (3,2) is on the line so substitute x = 3, y = 2 in this equation to give: 2 = 5*3 + c or 2=15+c Then subtract 15 off both sides as to calculate c. 2-15=-13 so that c = -13 Therefore the equation is y = 5x - 13
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