It helps to think as the sine and cosine as coordinates of a unit circle - a circle of radius 1, with center at the origin of the coordinates, i.e., point (0, 0). In this case, as you go around on the circle (starting at the right, coordinates (1, 0), and going counterclockwise), the cosine of the angle is simply the x-coordinate, and the sine of the angle is simply the y-coordinate. At 90°, the x-coordinate is 0, therefore the cosine is 0. Also, at 90° the y-coordinate is 1, therefore the sine is 1 (that's the maximum value it can have).
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The cosine of 90 degrees is zero.
Just like the sine function displaced by pi/2. In other words the cosine equals 1 at 0 degrees, 0 at 90 degrees, -1 at 180 and so on.
First, I assume the question refers to tan(90 degrees) not Ten90' because (apart from the incorrect spelling of tan) 90' represents 90 minutes or 90/60 degrees = 1.5 degrees. The tangent of an angle is defined as the ratio of sine to cosine of the angle. When that angle is 90 degrees, the cosine is zero and so calculation of tan involves division by 0. And, in mathematics division by 0 is not infinity - it is not defined. So, tan(90) is NOT infinity. It is not defined. tan90 has a positive asymptote when you approach 90 degrees from below but has a negative asymptote when you approach from above.
The cosine of 8 degrees is 0.99026806874157031508377486734485
The inverse of the cosine function is arcosine. The domain is −1 ≤ x ≤ 1 since the range of the cosine function is from -1 to 1. The range is from 0 to pi radians or 0 to 180 degrees.