Cosine of -90 is 0.
Reciprocal of Cosine is Secant
it would be secant, 1/cosine
No, not necessarily. Cosine theta is equal to 1 only when theta is equal to zero and multiples of 2 pi radians or multiples of 360 degrees. This is because cosine theta is hypotenuse over adjacent, and the ratio 1 only occurs at 0, 360, 720, etc. or 0, 2 pi, 4 pi, etc.
[ cos(Θ) ]-1 = 1/cosine(Θ) = secant(Θ)
Cosine (0) = 1 Sin(0) = 0 The sine and cosine curves are two intertwining curves, that complement each other, hence the words 'Sine (Curve) and Cosine ( COmplementary Curve).
Cosine of -90 is 0.
If the numerator is 0 AND the denominator is not 0, then the ratio is 0. And cosine of 0 is 1.
The Y-Intercept of the cosine function is X = 0, Y = cosine(0) = 1.
Secant is 1 over cosine and cosine 0 equals 1.
Tangent = sine/cosine provided that cosine is non-zero. When cosine is 0, then tangent is undefined.
It is 1.
sin 0 = 0 cos 0 = 1
The inverse of the cosine function is arcosine. The domain is −1 ≤ x ≤ 1 since the range of the cosine function is from -1 to 1. The range is from 0 to pi radians or 0 to 180 degrees.
The sine graph and the cosine graph are identical in shape, with the cosine graph shifted to the left by pi / 2, i.e. the sine starts at (x=0,y=0) and proceeds up with an initial slope of one, and the cosine starts at (x=0,y=1), and proceeds down with an initial slope of zero.
Zero. Tangent = sine/cosine. sin(0) = 0 and cos(0) = 1, so 0/1 = 0.
int main (void) { puts ("Cosine of 60° is 1/2"); return 0; }