Your equation has two variables in it ... 'a' and 'x'. So the solution is a four-step process: 1). Get another independent equation that relates the same two variables. 2). Solve one of the equations for one of the variables. 3). Substitute that into the other equation, yielding an equation in a single variable. Solve that one for the single variable. 4). Substitute that value back into the first equation, and solve it for the second variable.
To solve a whole number equation, follow these steps: Simplify both sides of the equation by combining like terms. Use inverse operations to isolate the variable on one side of the equation. Perform the necessary operations to solve for the variable. Check your solution by substituting the value back into the original equation to ensure it satisfies the equation.
To verify your answers in a math problem it is best to work backwards. For example if you were dividing 4 by 2 and you get the answer 2 you would check it by multiplying 2 time 2. If it is an algebraic equation you can simply substitute the answer back into the original equation. Example with the problem 2X + 1 = 5 and you get the answer X=2 you simply substitute 2 back into the original problem for X...... 2(2) + 1 = 5
when you're really good in that kind of equation, but cannot, no matter what u do, CANNOT figure it out! when you look it up and can't find the answer in the back of the book. It depends on what kind of problem it is.
Plug your answer back into the original equation.Example:3x+15=21x=23(2)+15=21
Substitute the value found back into the equation, evaluate the expressions and see if the resulting equation is true.
If you found the value of x that is a solution to an equation, you want to substitute that value back into the original equation, to check that it indeed satisfies the equation. If it does not satisfy the equation, then you made an error in your calculations, and you need to rework the problem.
plug your solution back into the original equation and work it out again
Your equation has two variables in it ... 'a' and 'x'. So the solution is a four-step process: 1). Get another independent equation that relates the same two variables. 2). Solve one of the equations for one of the variables. 3). Substitute that into the other equation, yielding an equation in a single variable. Solve that one for the single variable. 4). Substitute that value back into the first equation, and solve it for the second variable.
A solution of a linear equation is called a root or a solution. It is a value that satisfies the equation when substituted back into it.
1) Replace the inequality signs in the solution and in the original question with = signs. Substitute the solution inn the question: it should make it true. 2) (Back to the inequalities) Pick another number that satisfies the solution inequality - e.g. if x>2, pick 5. Substitute this into the original inequality: if it makes it true, then you are good to go!
To solve a whole number equation, follow these steps: Simplify both sides of the equation by combining like terms. Use inverse operations to isolate the variable on one side of the equation. Perform the necessary operations to solve for the variable. Check your solution by substituting the value back into the original equation to ensure it satisfies the equation.
To verify your answers in a math problem it is best to work backwards. For example if you were dividing 4 by 2 and you get the answer 2 you would check it by multiplying 2 time 2. If it is an algebraic equation you can simply substitute the answer back into the original equation. Example with the problem 2X + 1 = 5 and you get the answer X=2 you simply substitute 2 back into the original problem for X...... 2(2) + 1 = 5
when you're really good in that kind of equation, but cannot, no matter what u do, CANNOT figure it out! when you look it up and can't find the answer in the back of the book. It depends on what kind of problem it is.
Plug your answer back into the original equation.Example:3x+15=21x=23(2)+15=21
To solve this system of equations, we can use the method of substitution or elimination. Let's use the substitution method. From the second equation, we can express y as y = 55 - 4x. Substitute this expression for y in the first equation: 7x - 5(55 - 4x) = 76. Simplify this equation to solve for x. Then, substitute the value of x back into one of the original equations to find the value of y.
rewrite first equation: x = 15 - y substitute into second equation for x: 4(15 - y) + 3y = 38 distribute and simplify: 60 - y = 38 solve: y = 22 plug back into first equation: x = -7 -OR- multiply first equation by -3: -3x - 3y = -45 add new equation to second equation: 1x + 0y = -7 or x = -7 plug back into first equation: y = 22