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Q: Why regular languages are not closed under infinite union?
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Related questions

How can you prove that the complement of a regular language is regular?

The complement of a regular language is regular because regular languages are closed under complementation. This means that if a language is regular, its complement is also regular.


Are decidable languages closed under concatenation?

Yes, decidable languages are closed under concatenation.


Are decidable languages closed under intersection?

Yes, decidable languages are closed under intersection.


Are recognizable languages closed under concatenation?

Yes, recognizable languages are closed under concatenation.


Is the class of recognizable languages closed under complementation?

No, the class of recognizable languages is not closed under complementation.


Is the class of undecidable languages closed under complementation?

No, the class of undecidable languages is not closed under complementation.


Is the set of nonregular languages closed under intersection?

No, the set of nonregular languages is not closed under intersection.


Are Turing recognizable languages closed under concatenation?

Yes, Turing recognizable languages are closed under concatenation.


Are Turing recognizable languages closed under intersection?

Yes, Turing recognizable languages are closed under intersection.


Are Turing recognizable languages closed under union?

Yes, Turing recognizable languages are closed under union.


Are context-free languages closed under concatenation?

Yes, context-free languages are closed under concatenation.


What are the closure properties of regular sets?

;: Th. Closed under union, concatenation, and Kleene closure. ;: Th. Closed under complementation: If L is regular, then is regular. ;: Th. Intersection: .