There is no reason why it should! So the question is based on an incorrect assumption. A matrix of only zero vectors will be singular!
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A non-singular matrix is basically one that has a multiplicative inverse. More specifically, a matrix "A" is non-singular if there is a matrix "B", such that AB = BA = 1, where "1" is the unity matrix. Non-singular matrixes are those that have a non-zero determinant. Singular and non-singular matrixes are only defined for square matrixes.
Call your matrix A, the eigenvalues are defined as the numbers e for which a nonzero vector v exists such that Av = ev. This is equivalent to requiring (A-eI)v=0 to have a non zero solution v, where I is the identity matrix of the same dimensions as A. A matrix A-eI with this property is called singular and has a zero determinant. The determinant of A-eI is a polynomial in e, which has the eigenvalues of A as roots. Often setting this polynomial to zero and solving for e is the easiest way to compute the eigenvalues of A.
A zero matrix is a matrix in which all of the entries are zero.
If all the components of a vector are zero, the magnitude of the vector will always be zero.
The zero vector is both parallel and perpendicular to any other vector. V.0 = 0 means zero vector is perpendicular to V and Vx0 = 0 means zero vector is parallel to V.