First, showing the equation in a different way will help solve it
n/(n/2) +0.3
as n/(n/2) is equal to 2n/n (which can be further simplified to 2), the result for the equation wil be 2.3 no matter what value n has.
example for n/(n/2)=2n/n/2
let n=4
4/(4/2)
=4/(2)
=2
You cannot define a line with a single point (a single point only defines itself). You need two points to define a line (and therefore to write the equation for it).
Substitute the coordinates of the point into the equation and if the result is a true statement then the point is a solution, and if not it isn't.
Yes it is the equation for a vertical line (parallel to the y-axis), intersecting the x-axis at the point (3,0). There is not a y component in this equation, because at any value of y, x will always equal 3.
Yes, the graph of the equation ( y = ax ) will always intersect the origin (0,0) regardless of the value of ( a ). This is because when ( x = 0 ), the equation simplifies to ( y = a \cdot 0 = 0 ), indicating that the point (0,0) is always on the graph. Therefore, the graph will always pass through the origin.
If the algebraic equation is linear, in the form y = mx + b, the slope is simply m; the difference in y of any 2 points divided by the difference in x of those points (rise over run). If the equation is non-linear, the slope is the first derivative of that equation, from calculus. You woul need to know calculus to solve in this case. The slope will vary from point to point, unlike the linear case, where slope is constant.
You cannot define a line with a single point (a single point only defines itself). You need two points to define a line (and therefore to write the equation for it).
i always know that 7 divided by 2 = 8,0000
The y-axis has the equation x=0, so every point on the y-axis has an x coordinate of zero.
i always know that 7 divided by 2 = 8,0000
Substitute the coordinates of the point into the equation and if the result is a true statement then the point is a solution, and if not it isn't.
Roman numerals were used by the ancient Romans for the purposes of addition, subtraction, division and multiplication.
Substitute the coordinates of the point into the equation of the line. If the equation is still valid then the point is on the line; if not then it is not.
Yes it is the equation for a vertical line (parallel to the y-axis), intersecting the x-axis at the point (3,0). There is not a y component in this equation, because at any value of y, x will always equal 3.
Yes, the graph of the equation ( y = ax ) will always intersect the origin (0,0) regardless of the value of ( a ). This is because when ( x = 0 ), the equation simplifies to ( y = a \cdot 0 = 0 ), indicating that the point (0,0) is always on the graph. Therefore, the graph will always pass through the origin.
If the algebraic equation is linear, in the form y = mx + b, the slope is simply m; the difference in y of any 2 points divided by the difference in x of those points (rise over run). If the equation is non-linear, the slope is the first derivative of that equation, from calculus. You woul need to know calculus to solve in this case. The slope will vary from point to point, unlike the linear case, where slope is constant.
A line is represented by an equation. Each solution of the equation is a point on the line, and each point on the line is a solution to the equation. So the line is just the graph of the solution set of the equation.
To determine if the point (1, 1) satisfies the equation ( y = 6x ), we can substitute ( x = 1 ) into the equation. This gives us ( y = 6(1) = 6 ). Since the point has ( y = 1 ) but the equation gives ( y = 6 ), the point (1, 1) does not satisfy the equation.