Yes, in a normal distribution, the mean is always equal to the median. This is because the normal distribution is symmetric around its mean, meaning that the values are evenly distributed on both sides. As a result, the central tendency measured by both the mean and the median coincides at the same point.
Yes, mode equals median in a normal distribution.
Yes.
Mean, median, and mode are all equal in a normal distribution.
Yes.
In a symmetric distribution, the mean and median will always be equal. This is because symmetry implies that the distribution is balanced around a central point, which is where both the mean (the average) and the median (the middle value) will fall. Therefore, in perfectly symmetric distributions like the normal distribution, the mean, median, and mode coincide at the center. In practice, they may be approximately equal in symmetric distributions that are not perfectly symmetrical due to rounding or sampling variability.
Yes, mode equals median in a normal distribution.
Yes.
Yes.
Mean, median, and mode are all equal in a normal distribution.
Yes.
No. They are equal only if the distribution is symmetrical.
In a normal distribution, the mean, median, and mode are all equal. Therefore, if the mean is 40, the median is also 40. This property holds true for any normal distribution regardless of its specific values.
The mean, median, and mode of a normal distribution are equal; in this case, 22. The standard deviation has no bearing on this question.
In a normal distribution, the mean, median, and mode are all equal. Therefore, if both the mean and the mode are 25, the median would also be 25. This property is a defining characteristic of normal distributions.
True. You can find many references including wikipedia on the Normal distribution on the internet.
No.
Yes, and they WILL be if the distribution is symmetrical.