Point: (2, 17)Slope: 7Equation: y = 2x+13
The slope intercept form through 23 and 15 would be 5. This is considered as a math equation.
The standard form of the equation is 2x - y + 5 = 0
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
You place X and Y on the same side to get a standard equation.
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
The standard form is: 5x - y + 4 = 0
Point: (2, 17)Slope: 7Equation: y = 2x+13
The slope intercept form through 23 and 15 would be 5. This is considered as a math equation.
The equation of a line with an undefined slope is x = a.
The standard form of the equation is 2x - y + 5 = 0
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
slope 5/6 through (-18,6)
You place X and Y on the same side to get a standard equation.
in the equation y=mx+b where y is the y-axis, x is the x-axis, m is the slope, and b is the y intercept. You can also write the equation in standard fore, or point-slope form.
The standard form for a straight line equation is y = mx + c, where 'm' is the gradient (slope) and 'c' is the y intercept when 'x' is zero. The equation for the line with details as shown in the question is y = -2x - 4