To write the equation of a line in point-slope form that is parallel to ( y = \frac{1}{2}x + 3 ), we first note that the slope of the given line is (\frac{1}{2}). Using the point ((-1, 4)) and the slope (\frac{1}{2}), we apply the point-slope formula (y - y_1 = m(x - x_1)). This gives us the equation:
[ y - 4 = \frac{1}{2}(x + 1) ]
To write the equation of a line that is parallel to ( y = 23x - 2 ), you need to use the same slope, which is 23. The point through which the line passes is (-4, 7). You can use the point-slope form of the equation of a line: ( y - y_1 = m(x - x_1) ). Substituting in the slope (23) and the point (-4, 7), the equation becomes ( y - 7 = 23(x + 4) ), which simplifies to ( y = 23x + 99 ).
To find the slope-intercept form of the equation of a line parallel to ( y = 9x + 1 ) and passing through the point (1, 4), we first note that parallel lines have the same slope. The slope of the given line is 9. Using the point-slope form ( y - y_1 = m(x - x_1) ), we plug in the point (1, 4) and the slope 9: [ y - 4 = 9(x - 1) ] Simplifying this gives: [ y = 9x - 5 ] Thus, the slope-intercept form of the new line is ( y = 9x - 5 ).
Point: (2, 17)Slope: 7Equation: y = 2x+13
To write the equation of a line that is parallel to the line given by (y - 4x - 3 = 0), first determine the slope of the original line. Rearranging the equation to slope-intercept form (y = mx + b), we find the slope (m = 4). Since parallel lines have the same slope, the new line will also have a slope of 4. Using the point-slope form (y - y_1 = m(x - x_1)) with the point (5, 7), we can write the equation as (y - 7 = 4(x - 5)), which simplifies to (y = 4x - 13) in slope-intercept form.
If you mean passing through the point (-2, 1) then the parallel line will have the same slope but with a different y intercept.
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
Parallel straight line equations have the same slope but with different y intercepts
To write the equation of a line that is parallel to ( y = 23x - 2 ), you need to use the same slope, which is 23. The point through which the line passes is (-4, 7). You can use the point-slope form of the equation of a line: ( y - y_1 = m(x - x_1) ). Substituting in the slope (23) and the point (-4, 7), the equation becomes ( y - 7 = 23(x + 4) ), which simplifies to ( y = 23x + 99 ).
To find the slope-intercept form of the equation of a line parallel to ( y = 9x + 1 ) and passing through the point (1, 4), we first note that parallel lines have the same slope. The slope of the given line is 9. Using the point-slope form ( y - y_1 = m(x - x_1) ), we plug in the point (1, 4) and the slope 9: [ y - 4 = 9(x - 1) ] Simplifying this gives: [ y = 9x - 5 ] Thus, the slope-intercept form of the new line is ( y = 9x - 5 ).
If you mean y = 3x+8 then the parallel equation will have the same slope and works out as y = 3x+13
Both straight line equations will have the same slope or gradient but the y intercepts wll be different
Point: (2, 17)Slope: 7Equation: y = 2x+13
The equation in point slope of the line which passes through -2 -3 and is parallel to 3x plus 2y 10 is y=-1.5x.
To write the equation of a line that is parallel to the line given by (y - 4x - 3 = 0), first determine the slope of the original line. Rearranging the equation to slope-intercept form (y = mx + b), we find the slope (m = 4). Since parallel lines have the same slope, the new line will also have a slope of 4. Using the point-slope form (y - y_1 = m(x - x_1)) with the point (5, 7), we can write the equation as (y - 7 = 4(x - 5)), which simplifies to (y = 4x - 13) in slope-intercept form.
If you mean passing through the point (-2, 1) then the parallel line will have the same slope but with a different y intercept.
Slope of the line and the coordinates of a point on the line [for example (-3,2)]