If you mean passing through the point (-2, 1) then the parallel line will have the same slope but with a different y intercept.
False
False
Suppose the top face of the pyramid is ABCD with the square EFGH directly below it.Suppose AC and BD meet at P, the apex of the pyramid.Make a cut with a plane through P which is parallel to AB and goes through EF.Make a cut with a plane through P which is parallel to BC and goes through FG.Make a cut with a plane through P which is parallel to CD and goes through GH.Make a cut with a plane through P which is parallel to DA and goes through HE.The result will be the square-based pyramid PEFGH.
a transversal
To find the slope-intercept form of the equation of a line that goes through the point (2, 2) and is parallel to the line ( y = x + 7 ), we first identify the slope of the given line, which is 1. Since parallel lines have the same slope, the new line will also have a slope of 1. Using the point-slope form ( y - y_1 = m(x - x_1) ) with ( m = 1 ) and the point (2, 2), we can rewrite it as ( y - 2 = 1(x - 2) ), which simplifies to ( y = x ).
true
The line will have the same slope but with a different y intercept
False
False
The answer is FALSE i just did it on
The major line of latitude that goes through Ohio is the 40th parallel north.
Fold the paper so the line is on itself. Fold this folded edge on itself causing a crease to form that goes through the point in question, You are using the theorem that lines perpendicular to the same line are parallel.
Suppose the top face of the pyramid is ABCD with the square EFGH directly below it.Suppose AC and BD meet at P, the apex of the pyramid.Make a cut with a plane through P which is parallel to AB and goes through EF.Make a cut with a plane through P which is parallel to BC and goes through FG.Make a cut with a plane through P which is parallel to CD and goes through GH.Make a cut with a plane through P which is parallel to DA and goes through HE.The result will be the square-based pyramid PEFGH.
The gradient of the line y = -3 is 0. So any parallel line has the equation y = c.Since it goes though the point (2, 6), c = 6 and so the equation is y = 6.
a transversal
To find the slope-intercept form of the equation of a line that goes through the point (2, 2) and is parallel to the line ( y = x + 7 ), we first identify the slope of the given line, which is 1. Since parallel lines have the same slope, the new line will also have a slope of 1. Using the point-slope form ( y - y_1 = m(x - x_1) ) with ( m = 1 ) and the point (2, 2), we can rewrite it as ( y - 2 = 1(x - 2) ), which simplifies to ( y = x ).
The answer is: y = 1/2x + 4