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I assume you mean, (x-2)/(3x+5)=4?
If so, then the solution is simple. Multiply 3x+5 by 4, and distribute according to the left or right distributive property of the real numbers, this will give you x-2=12x+20. Subtract the 1x on the left from both sides, and the 20 on the right from both sides. This gives -22=11x.
Then divide by 11 on both sides to get -2=x, which is the same as x=-2 by the symmetric property.
The reason for subtraction and division on both sides is to ensure that you do not change the overall value, if I subtract from one side and not the other, then the value of the total equation changes. By performing the same operation on both sides, you are changing the equation by 0, the reason this works is the beauty of algebra, and the fact that x represents an unknown that you can play with.
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X2 plus 3x plus 10 equals 0?
-2
X2 plus 3x plus 7 equals 5?
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
If 3x-1 equals 11 what is the value of x2 plus 2?
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
-x2 plus 3x equals -4?
-2x + 3x = -4 By combining like terms we get: x = -4.
Y equals x2 plus 3x plus 2?
is a quadratic equation for y, in terms of x.
