x2 - x + 3 = 0
x = [1 +/- sqrt(1-12)]/2 = [1 +/- i*sqrt(11)]/2 where i is the imaginary square root of -1.
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3 + -3
(0, -3)
3 + 0 = 3
a = 3 and y = 0
Oh, dude, it's like so simple. 0 plus 3 equals 3. I mean, come on, even a potato could figure that one out.