0
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x2 - x + 3 = 0x = [1 +/- sqrt(1-12)]/2 = [1 +/- i*sqrt(11)]/2 where i is the imaginary square root of -1.
0+3=3
3 + -3
3 + 0 = 3
(0, -3)
a = 3 and y = 0
Zero
x = 0
2x^2 + 8x + 3 = 0
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
(2x + 1)(x + 3) = 0; x = -0.5 or -3
(1, 0)
(-1, 0)