Assuming you wish to make this equation equal zero, for x2 + 16x + 55 = 0, x = -5.
To factorise x3 + 5x2 - 16x - 80 I note that -80 = 5 x -16 and 5 & -16 are the coefficients of x2 and x. Thus I have: x3 + 5x2 - 16x - 80 = (x + 5)(x2 - 16) and the second term is a difference of 2 squares, meaning I have: x3 + 5x2 - 16x - 80 = (x + 5)(x + 4)(x - 4)
x2 + 16x - 348 cannot be factored. Solving for x with the quadratic formula results in x = -8 - 2√103 and x = -8 + 2√103
(x - 7)(x - 9)
That factors to (x - 14)(x - 2)
Assuming you wish to make this equation equal zero, for x2 + 16x + 55 = 0, x = -5.
x2 + 48x + 320
square root -5 minus 14 or - square root -5 minus 14
To factorise x3 + 5x2 - 16x - 80 I note that -80 = 5 x -16 and 5 & -16 are the coefficients of x2 and x. Thus I have: x3 + 5x2 - 16x - 80 = (x + 5)(x2 - 16) and the second term is a difference of 2 squares, meaning I have: x3 + 5x2 - 16x - 80 = (x + 5)(x + 4)(x - 4)
x2 + 16x - 348 cannot be factored. Solving for x with the quadratic formula results in x = -8 - 2√103 and x = -8 + 2√103
x2+16x-80 = 0 (x-4)(x+20) = 0 x = 4 or x = -20
x2-16x+48 = (x-4)(x-12) when factored
(x - 7)(x - 9)
x(x + 4)(x - 4) or x3 - 16x
x2 - 16x + 28 = x2 -2x - 14x - 28 = x(x - 2) - 14(x - 2) = (x - 14)(x - 2)
Y=(x+8)^2-5
Half of the coefficient of x, squared. For example: x2 + 16x -3 you would add 8^2. Then you would have: x2 +16x +8^2 = 3-8^2 Which leads to: (x+8)^2 = -61