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x2 + 4x + y2 - 6y = 3
You need to be more clear about your question:
Are you trying to find the properties of the curve it defines?
x2 + 4x + y2 - 6y = 3
∴ x2 + 4x + 4 + y2 - 6y + 9 = 16
∴ (x + 2)2 + (y - 3)2 = 42
∴ This describes a circle with a radius of 4, and a center point of (-2, 3)
Did you want to solve for y?
(x + 2)2 + (y - 3)2 = 42
∴ (y - 3)2 = 16 - (x + 2)2
∴ y - 3 = ± [16 - (x + 2)2]1/2
∴ y = 3 ± [16 - (x + 2)2]1/2
Did you want to solve for x?
(x + 2)2 + (y - 3)2 = 42
∴ (x + 2)2 = 16 - (y - 3)2
∴ x + 2 = ± [16 - (y - 3)2]1/2
∴ x = -2 ± [16 - (y - 3)2]1/2
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X2 plus y2 plus 4x - 2y - 5 equals 0?
No.
What is x2 plus 4x plus 4 equals 25?
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
Can you put the equation x2 plus 4x plus 10 equals 3 in the form ax2 plus bx plus c equals 0?
x^2+4x+7
2x equals x2 plus 4x-3?
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Solve x2 plus 4x plus 3 equals 0?
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