x2 + 4x + y2 - 6y = 3
You need to be more clear about your question:
Are you trying to find the properties of the curve it defines?
x2 + 4x + y2 - 6y = 3
∴ x2 + 4x + 4 + y2 - 6y + 9 = 16
∴ (x + 2)2 + (y - 3)2 = 42
∴ This describes a circle with a radius of 4, and a center point of (-2, 3)
Did you want to solve for y?
(x + 2)2 + (y - 3)2 = 42
∴ (y - 3)2 = 16 - (x + 2)2
∴ y - 3 = ± [16 - (x + 2)2]1/2
∴ y = 3 ± [16 - (x + 2)2]1/2
Did you want to solve for x?
(x + 2)2 + (y - 3)2 = 42
∴ (x + 2)2 = 16 - (y - 3)2
∴ x + 2 = ± [16 - (y - 3)2]1/2
∴ x = -2 ± [16 - (y - 3)2]1/2
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
No.
x^2+4x+7
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
y = 4x-3
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
No.
x^2+4x+7
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
y=-x^2+4x-3
Y = x2 + 4x + 11OK. That's very interesting.Is there a question ?
x2 + 4x - 9 = 5x + 3 ∴ x2 - x - 12 = 0 ∴ (x + 3)(x - 4) = 0 ∴ x ∈ {-3, 4}
x2 + 4x = 0 ⇒ x(x + 4) = 0 ⇒ x = 0 or x = -4
x(x+4) equals x2 plus 4x
You need to know the value of x