4x+8
x2 + 4x = 1 x2 + 4x - 1 = 0 in the quadratic formula (b2+- Sqr(4ac))/2a, a = 1 b = 4 c = -1 so x = 8 +- i
x2 + 4x - 96 = (x - 8)(x + 12).
x2 + 4x - 32 = (x + 8)*(x - 4)
x2+4x-32 = (x-4)(x+8) when factored
4x+8
x2 + 4x = 1 x2 + 4x - 1 = 0 in the quadratic formula (b2+- Sqr(4ac))/2a, a = 1 b = 4 c = -1 so x = 8 +- i
If [ x = -8 ], thenx2 - 4x + 9= (-8)2 - 4(-8) + 9= 64 + 32 + 9= 105
x2 + 4x - 96 = (x - 8)(x + 12).
x2 + 4x - 32 = (x + 8)*(x - 4)
x2+4x-32 = (x-4)(x+8) when factored
If: y = x2-4x+8 and y = 8x-x2-14 Then: x2-4x+8 = 8x-x2-14 So: 2x2-12x+22 = 0 Discriminant: 122-(4*2*22) = -32 Because the discriminant is less than 0 there is no actual contact between the given parabolas
x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)
4x+32=-4x+16x4x+32=12x-4x -4x32=8x/8 /84=x
X2 + 2X - 14 = 6X2 + 2X - 8 = 0what two products of - 8 = 2 ?(X +4)(X - 2)=========X = - 4X = 2
If: 4x+(-12) = 8 then 4x = 20 and x = 5
There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.