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x2 + 5x + 7 = 0; a = 1, b = 5, c = 7; D = b2 - 4ac = 52 - 4(1)(7) = 25 - 28 = -3

x = (-b +&- sq. root of D)/2a

x = (-5 +&- sq. root of -3)/2

x = [-5 +&- (sq. root of 3)i]/2

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Q: X2 plus 5x plus 7 equals 0 what is the solution?
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