x2 + 5x + 7 = 0; a = 1, b = 5, c = 7; D = b2 - 4ac = 52 - 4(1)(7) = 25 - 28 = -3
x = (-b +&- sq. root of D)/2a
x = (-5 +&- sq. root of -3)/2
x = [-5 +&- (sq. root of 3)i]/2
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x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
We can't calculate what it equals until we know the value of ' x '.
x2 + 4x - 9 = 5x + 3 ∴ x2 - x - 12 = 0 ∴ (x + 3)(x - 4) = 0 ∴ x ∈ {-3, 4}
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
X2 - 5X = 24 X2 - 5X - 24 = 0 (X - 8)(X + 3) X = 8 ----------------and X = - 3 --------------