Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
x2 + 9x + 20 = 0 ∴(x + 4)(x + 5) = 0 ∴x ∈ {-5, -4}
x2 + 14x + 45 = 0 => x2 + 9x + 5x + 45 = 0 => x(x + 9) + 5(x + 9) = 0 (x + 9)(x + 5) = 0 so that x = -5 or x = -9
If you mean: x2+9x+20 then it is (x+4)(x+5) = 0 when factored
16
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
x2 + 9x + 20 = 0 ∴(x + 4)(x + 5) = 0 ∴x ∈ {-5, -4}
x2 + 14x + 45 = 0 => x2 + 9x + 5x + 45 = 0 => x(x + 9) + 5(x + 9) = 0 (x + 9)(x + 5) = 0 so that x = -5 or x = -9
If you mean: x2+9x+20 then it is (x+4)(x+5) = 0 when factored
-5
x = 2
It is (x+4)(x+5) when factored
53
It is: 5/9x-y+2 = 0
16
x = 5