9x2 + 8x - 1 = (9x - 1)(x + 1)
(x+1)(x+8)
(3x - y+ 2)(3x + y + 2)
(9x)2 +9x/(45x)2 +81= 9+9x/86
x2-9x+8=0 has two solutions:x = 8x = 1
Type your answer here... 81
9x2 + 8x - 1 = (9x - 1)(x + 1)
3(x2 + 3x + 1)
(x+1)(x+8)
(3x - y+ 2)(3x + y + 2)
You don't need to factor that; you can add them together, since they have the same variable.However, assuming you might mean 81x squared + 9x, you can take out the common factor, which is 9x.
(9x)2 +9x/(45x)2 +81= 9+9x/86
(2x+3)(x+3)
x2-9x+8=0 has two solutions:x = 8x = 1
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
9x squared plus 16 = 0 factored is plus and minus 4/3 i.
(x + 12)(x - 3)