Assuming that by sticking a question mark after that equation, you wish to solve it for x, it can be done this way:
x = x2 + 4x - 2
x2 + 3x = 2
x2 + 3x + 9/4 = 2 + 9/4
(x + 3/2)2 = (8 + 9)/4
x + 3/2 = ± √(17/4)
x = -3/2 ± √17/2
x = (-3 ± √17) / 2
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5x2-2x+16=4x2+6x ,or x2-8x+16=0, or x2-2(x)(4)+(4)2=0, or (x-4)2=0, or (x-4)(x-4)=0, or x=4
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
x2+8x = -3x2+5 4x2+8x-5 = 0 (2x+5)(2x-1) = 0 x = -5/2 or x = 1/2
Subtract 9 from each side: 4x2 + 4x - 8 = 0Simplify: 4(x2 + x - 2) = 0Factorise: 4(x + 2)(x - 1) = 0So x = -2 or 1 both of which satisfy the original equation.
4x2 -x -1 :D