-((4x + 1)(x - 1))
The answer is: x = -5/2 and x = 7/2
4x2-5x+1 = 0 (4x-1)(x-1) = 0 x = 1/4 or x = 1
4x2 - 4x + 2xy - 2y = 4x(x - 1) + 2y(x - 1) = (x - 1)(4x + 2y) = 2(x - 1)(2x + y)
4x2 - 13 x + 3 = 0 (4x - 1)(x - 3) = 0 x = 3, 1/4
-((4x + 1)(x - 1))
4x2-4x+1 = (2x-1)(2x-1)
The answer is: x = -5/2 and x = 7/2
Given, 4x2 - 4x + 3 = 0; then, 4x2 - 4x + 1 = (2x - 1)2 = -2, 2x - 1 = √-2 = ±i√2, and 2x = 1 ± i√2; therefore, x = ½(1 ± i√2).
4x2 - 4x + 2xy - 2y = 4x(x - 1) + 2y(x - 1) (4x + 2y)(x - 1).
4x2-5x+1 = 0 (4x-1)(x-1) = 0 x = 1/4 or x = 1
4x2 - 4x + 2xy - 2y = 4x(x - 1) + 2y(x - 1) = (x - 1)(4x + 2y) = 2(x - 1)(2x + y)
4x2 - 13 x + 3 = 0 (4x - 1)(x - 3) = 0 x = 3, 1/4
If you meant 2x+3=4x²x=(1±√(13))/4x1≈1.151387818866x2≈-0.651387818866
4x2 - 4x + 1 = 0 => (2x - 1)(2x - 1) = 0 => (2x - 1)2 = 0 There is one solution: x = 1/2. It is a repeated root of the equation.
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
(4x + 1)(x + 5)