Presumably this is a simultaneous equation question which can be solved using the elimination method?
4(x+2y = -1)
4x+3y = -9
First multiply all terms in the top equation by 4:
4x+8y = -4
4x+3y = -9
Subtract the bottom equation from the top equation in order to eliminate x remembering that a - - is equal to a + So -4 - -9 is equal to 5:
5y = 5 => y = 1
Substitute the value of y into the original equations to find the value of x:
Therefore: x = -3 and y = 1
You need to organise your question properly. 3x+2y=4 4x + 3y= 7? Is 4 4x = 44x or 4-4x or 4+4x How can there be 2 equal signs in 1 equation?
3y2 - 2y + 6xy - 4x = y(3y - 2) + 2x(3y - 2) = (y + 2x)*(3y - 2)
Yes and their solutions are x = 41 and y = -58
3x + y
-4x + 3y = 9
4x + 3y = 8x + y so 3y - y = 8x - 4x ie 2y = 4x so y = 2x
You need to organise your question properly. 3x+2y=4 4x + 3y= 7? Is 4 4x = 44x or 4-4x or 4+4x How can there be 2 equal signs in 1 equation?
3y2 - 2y + 6xy - 4x = y(3y - 2) + 2x(3y - 2) = (y + 2x)*(3y - 2)
5x + (3y-x) + (10-2y) = 5x + 3y - x + 10 -2y = 5x - x + 3y - 2y + 10 = 4x + y +10
4x-2y
4x+3y-2x+y 4x-2x+3y+y 2x+4y Taking out 2 common 2(x+2y) Hence the required answer is 2(x+2y)
Yes and their solutions are x = 41 and y = -58
3x + y
It simplifies to: 12x+3y
5x+3y
-4x + 3y = 9
4x + 3y = 4 x - 2y = -10, so add 2y to both sides gives x=2y-10, replace this into first equation gives: 4(2y-10) + 3y = 4, expand that gives 8y-40+3y=4, add 40 to both sides, this gives: 8y + 3y =44, or 11y = 44 giving you y=4. You have solved for y, now solve for x: 4x + 3y = 4, gives 4x +12 = 4, or 4x=-8 giving x=-2. So x=-2 and y=4. QED.