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x + 7y = 33 (1) --> x = 33 - 7y (1a)

3x - 2y = 7 (2)

To solve the simultaneous equations, starts by substituting the value for x found in (1a) into (2):

3(33 - 7y) - 2y = 7

99 - 21y - 2y = 7

-23y = -92

y = 4

Now substitute this value for y into (1a) and solve for x:

x = 33 - 7(4)

x = 33 - 28

x = 5

Therefore these equations have the solution x = 5, y = 4

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12y ago
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Q: X plus 7y equals 33 and 3x - 2y equals 7?
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