x + 7y = 33 (1) --> x = 33 - 7y (1a)
3x - 2y = 7 (2)
To solve the simultaneous equations, starts by substituting the value for x found in (1a) into (2):
3(33 - 7y) - 2y = 7
99 - 21y - 2y = 7
-23y = -92
y = 4
Now substitute this value for y into (1a) and solve for x:
x = 33 - 7(4)
x = 33 - 28
x = 5
Therefore these equations have the solution x = 5, y = 4
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3x + 2y = 7
(2, -1)
3x-2y-7=0
3x+2y = 1 2y = -3x+1 y = -1.5x+0.5
3x+2y=6 2y=-3x+6 y=-1.5x+3