Put all the terms on the left side: x2 - 6x - 112 = 0. Then use the quadratic formula, or find suitable factors. The quadratic formula is: If ax2 + bx + c = 0, then x = (-b plusminus root(b2 - 4ac)) / 2a; in this case, a = 1, b = -6, c = -112.
{-1,7}
When factored it is: (6x-1)(6x+1)
-116
x2 - 6x - 27 = (x-9)(x+3)
3x(6x - 1)
(6x - 1)(6x - 1)
x-8
It is: (2x+3)(3x-8) when factored
It is: 3x2+6x-11 = 0
First, factorising, we get: x2 - 6x - 16 = (x - 8)(x + 2). Then, (x2 - 6x - 16) / (x - 8) = x + 2.
6x - 4y
x = 2