0
(18x^(2) - 3x)
'3x' is a common factor to both terms , so 'take it out'.
Hence
3x(6x - 1)
Fully factored.
What else can I help you with?
How do you factor 18x squared yz plus 12xy squared z plus 6xyz squared?
6xyz(3x + 2y + z)
How do you factor 3x squared minus 1x minus 2?
3x2-x-2 = (3x+2)(x-1)
How do you factor 6x squared minus 7x minus 24?
It is: (2x+3)(3x-8) when factored
How do you factor 20x squared minus 3x plus 10?
20x2 - 3x + 10 does not have any real factors.
What is Factor x squared plus 3x minus 54?
(x - 6)(x + 9)
How do you factor 9x cubed plus 18x squared minus x minus 2?
(x + 2)(3x - 1)(3x + 1)
How do you you factor 3x squared minus 25x minus 28?
3x squared minus 25x minus 28
How do you factor 18x squared plus 9xt plus t squared?
(6x + t)(3x + t)
Factor 3x cubed plus 15x squared plus 18x?
3x3+15x2+18x = 3x(x2+5x+6) = 3x(x+2)(x+3)
How do you factor 18x squared yz plus 12xy squared z plus 6xyz squared?
6xyz(3x + 2y + z)
Who can factor 3x squared minus 2x?
x(3x - 2)
How do you factor 3x squared minus 8x minus 3?
(x-3)(3x+1)
Factor the polynomial 3x squared minus 14x minus 5?
(3x + 1)(x - 5)
How do you factor 9x squared minus 64?
(3x + 8)(3x - 8)
How do you factor 3x squared plus 9x minus 2x minus 6?
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
How do you solve 9x squared plus 18x minus 16 equal 0?
9x2 + 18x - 16 = 0 ⇒ (3x - 2)(3x + 8) = 0 ⇒ 3x - 2 = 0 → x = 2/3 or 3x + 8 = 0 → x = -22/3
How do you factor 3x squared minus 1x minus 2?
3x2-x-2 = (3x+2)(x-1)
