X2+3x-6=0
A=1
B=3
C=-6
D=B2-4AC=32-4*1*-6=33
X1= (-B+√D)/(2A)=(-3+√33)/(2*6)=1,372281323
X2= (-B-√D)/(2A)=(-3-√33)/(2*6)=-4,372281323
(x - 6)(x + 9)
That factors to (x - 3)(x + 6)
6x^2 -13x+6 = (3x-2)(2x-3) when factorized
(x - 3)(x^2 + 6)
No
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
(x - 6)(x + 9)
That factors to (x - 3)(x + 6)
6x2 + 5x - 6 is factored out to (2x + 3)(3x - 2).
6x^2 -13x+6 = (3x-2)(2x-3) when factorized
(x - 3)(x^2 + 6)
Let square = [x] -4+3*(-2)*[-4]+[3x-2x]=-4-6-2+[x]=-12+[x]The answer is negative 12 plus squared x.
3x2 -14x -24 can be factored as (3x + 4)(x - 6).
No
Because (x plus 3x) is 4x, and (-5 + 11) is 6.
This simplifies to 3x-6+4y.
-6 + 3x - y - 4x + 4y + 5 (combine like terms) = (-6 + 5) + (3x - 4x) + (-y + 4y) = -1 - x + 3yHope this helps :)