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X varies directly with y and z x equals 400 when y equals 8 and z equals 10 Find x when y equals 10 and z equals 12?
x = 5.y.z so 5.10.12 = 600
If m varies directly as n and inversely as o and m equals 20 when n equals 50 and o equals 10 find m when n equals 96 and o equals 16?
m = 24
X varies directly with y and inversely with z x equals 20 when y equals 8 and z equals 4 Find x when y equals 4 and z equals 8?
The answer is x=10. If: x=20 y=8 z=4 then: y=8/2=4 z=4*2=8 since x varies directly with y, meaning whatever happens to y, happens to x, so if y was divided by 2, then x should be divided by 2. After all, the inverse of division is multiplication.
Given y varies directly as x and y equals 125 when x equals 25what is the value of y when x equals 2?
y varies directly as x so y = cx for some constant c. y = 125 when x = 25 so 125 = c*25 so that c = 5 ie the relationship is y = 5x Then when x = 2, y = c*x = 5*2 = 10
If X varies inversely as Y and X equals -24 when Y equals 15 find X when Y equals -36?
xy = is a constant (k) so k = -360. When y = - 36, x = 10
Find an equation of variation where y varies directly as x and y equals 8 when x equals 2 find y when x equals 10?
40
Find an equation of variation where y varies directly as x and y equals 2 when x equals 10 find y when x equals -25?
y = -5
X varies directly with y and inversely with z x equals 0.25 y equals 10 and z equals 20 find x when y is 20 and z is 10?
1
Find an equation of variation where y varies directly as x and y equals 10 when x equals 5 find y when x is 4?
y = 8
X varies directly with y and z x equals 400 when y equals 8 and z equals 10 Find x when y equals 10 and z equals 12?
x = 5.y.z so 5.10.12 = 600
If m varies directly as n and inversely as o and m equals 20 when n equals 50 and o equals 10 find m when n equals 96 and o equals 16?
m = 24
What is the constant of variation if y varies directly with x and if y equals 500 when x equals 10?
50
Find the variation constant and an equation of variation where y varies directly as x and y equals 10 when x equals 37?
y = kx: 10 = 37k so k = 10/37 and y = 10x/37
If y varies directly with x and y equals 10 when x equals 5 what is the value of k?
We write y=kx since y varies directly as x. Now we know if x is 5, y is 10. so we write 10=5k so k=2
X varies directly with y and inversely with z x equals 20 when y equals 8 and z equals 4 Find x when y equals 4 and z equals 8?
The answer is x=10. If: x=20 y=8 z=4 then: y=8/2=4 z=4*2=8 since x varies directly with y, meaning whatever happens to y, happens to x, so if y was divided by 2, then x should be divided by 2. After all, the inverse of division is multiplication.
If c varies jointly as f and g and c equals 27 and f equals 18 and g equals 6 find c when f equals 30 and g equals 10?
x = 75
If y varies directly as x and y equals fifteen and when x equals 6 find y when x equals 10?
y = x/k so 15 = 6/k making k = 0.4. when x = 10 y = 10/0.4 ie 25 alternatively y/x = k ie 15/6 = k so k = 2.5; y/10 = 2.5 making y = 25.
