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There are several steps involved in how one can solve the derivative x plus y - 1 equals x2 plus y2. The final answer to this math problem is y'(x) = (1-2 x)/(2 y-1).
y = x2 + 14x + 21 a = 1, b = 14 x = -b/2a = -14/2*1 = -7
y = x / (x^2 + 2x + 1) The horizontal asymptote is y = 0
y = x2 - 6x + 2 y = x2 - 6x + 9 - 7 y = (x - 3)2 - 7
If you mean: y^2 + x^2 = 65 and y + x = 7 then the solutions are as follows:- When y = -1 then x = 8 When y = 8 then x = -1