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Can -0.2 express a probability?
No, we can't expression any negative value as a probability. A probability ranges from 0 to 1 - 0 being the lowest and 1 being the highest.
How do the highest and lowest possible values for the variable compare in their probability of occurring to the values in the middle of the distribution?
The answer will depend on the skewness of the distribution.The Poisson distribution is defined for non-negative integers: 0, 1, 2, 3, 4 etc. So the lowest value is 0.For a Poisson distribution with parameter l=1 (when it is very skew), the probability of the lowest two values, 0 and 1, is 0.368 each and the probability tails off rapidly for higher values.The answer will depend on the skewness of the distribution.The Poisson distribution is defined for non-negative integers: 0, 1, 2, 3, 4 etc. So the lowest value is 0.For a Poisson distribution with parameter l=1 (when it is very skew), the probability of the lowest two values, 0 and 1, is 0.368 each and the probability tails off rapidly for higher values.The answer will depend on the skewness of the distribution.The Poisson distribution is defined for non-negative integers: 0, 1, 2, 3, 4 etc. So the lowest value is 0.For a Poisson distribution with parameter l=1 (when it is very skew), the probability of the lowest two values, 0 and 1, is 0.368 each and the probability tails off rapidly for higher values.The answer will depend on the skewness of the distribution.The Poisson distribution is defined for non-negative integers: 0, 1, 2, 3, 4 etc. So the lowest value is 0.For a Poisson distribution with parameter l=1 (when it is very skew), the probability of the lowest two values, 0 and 1, is 0.368 each and the probability tails off rapidly for higher values.
Two six sided dice are rolled which number has the lowest probability of being rolled?
If two six sided fair dice are rolled, the sum of the result of both dice that has the lowest probability to come up is 2 and 12. P(2) = 1/36. P(12) = 1/36.
Who is lowest terms?
Nobody is lowest term. "Lowest term" is a mathematical expression, not a person!
What are the odds of hitting 2 straits in a row at 5 card stud?
The odds of hitting 2 straights in a row at 5 card stud is about 5%. Since the deck is reshuffled between deals, the two hands are sequentially unrelated, so the odds of two deals with two straights is simply th odds of one times the odds of another. In order to draw a straight, you need to draw an ace, 2, 3, 4, 5, or a 10, jack, queen, king, ace, assuming that ace can be high or low. The odds of drawing one of these cards is 10 in 13, but you have 5 chances to do so, so the odds of drawing the first card is 50 in 13. The odds of drawing the second card is 39 in 51, but you have 4 chances to do so, so the odds of drawing the second card is 156 in 51. Similarly, the odds of drawing the third, fourth, and fifith card is 38 in 50, 37 in 49, and 36 in 48. Multiply these odds and you get 19,740,240 in 77,968,800. Reducing that to lowest terms, you get 246,753 in 1,112,110, which is the odds of drawing a straight. The numeric value of the odds is 0.22187823146990855221156180593646, or about 22% Square that and you get 60,887,043,009 in 1,236,788,652,100. That is aready in lowest terms, so that is the odds of drawing two sequential straights. The numeric value of the odds is 0.049229949600214317813758989938262, or about 5%.
