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This is a sampling problem where the entire population is selected and there is no replacement. The chance of selecting all cities in alphabetical order is: (1/10)*(1/9)*(1/8)*(1/7)*(1/6)*(1/5)*(1/4)*(1/3)*(1/2) of 1/(10!) = 2.75 e-7. If we consider alphabetical order can be highest to lowest or lowest to highest, then the probability doubles or: 2/(10!)

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Q: A tourist in France wants to visit 10 different cities If the route is randomly selected what is the probability that she will visit the cities in alphabetical order?
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