This is a sampling problem where the entire population is selected and there is no replacement. The chance of selecting all cities in alphabetical order is: (1/10)*(1/9)*(1/8)*(1/7)*(1/6)*(1/5)*(1/4)*(1/3)*(1/2) of 1/(10!) = 2.75 e-7. If we consider alphabetical order can be highest to lowest or lowest to highest, then the probability doubles or: 2/(10!)
Non probability sampling is where the samples are not selected randomly.
The answer depends on the demography of the population from which the person is randomly selected.The answer depends on the demography of the population from which the person is randomly selected.The answer depends on the demography of the population from which the person is randomly selected.The answer depends on the demography of the population from which the person is randomly selected.
The answer will depend on what the disease is.
85/500 = 17%
The answer is 0.1586
Non probability sampling is where the samples are not selected randomly.
The answer depends on the demography of the population from which the person is randomly selected.The answer depends on the demography of the population from which the person is randomly selected.The answer depends on the demography of the population from which the person is randomly selected.The answer depends on the demography of the population from which the person is randomly selected.
15 19
The answer will depend on what the disease is.
10/12
85/500 = 17%
If the events can be considered independent then the probability is (0.7)4 = 0.24 approx.
The answer is 0.1586
It is approx 0.001824
There is not enough information about the the distribution of the number of people known by each individual - nor the averages. It is therefore no possible to give an answer any more precise than "the probability will be infinitesimally small".
It is 0.73 = 0.343
Using the Poisson approximation, the probability is 0.0418