The pace would be 6.32 miles per hour.
you divide to get miles per hour and then multiply that by 9
90 minutes = 1.5 hours. So, 1.5 x 9 = 13.5 miles.
Simply add your times and divide by the distance (or visa-versa).21 minutes + 63 minutes = 84 minutes84 minutes/10 miles = 8.4 minute miles.Note, this is a convenient form to calculate speed for runners. However, the "standard" would be in MPH (or the metric equivalent).(10 miles / 84 minutes)*(60 minutes/hour) = 7.14 MPHA common fallacy might be to calculate the speed in each leg of the race and average.3 miles in 21 minutes = 7 minute miles.7 miles in 63 minutes = 9 minute miles.If you average these two you get 8 minute miles WHICH IS INCORRECT.The problem with this is that the runner ran each pace for different distances. If the distances at each pace were the same, then this would work.
9 mph
The pace would be 6.32 miles per hour.
Speed = Distance/TimeSpeed*Time = Distance9*0.75 = 6.75 milesNote that 45 minutes is 0.75 of an hour.
it means run 9 miles doing each mile in 9 minutes and 11seconds( or in about 9min 7secs if the .11 is a decimal)
you divide to get miles per hour and then multiply that by 9
90 minutes = 1.5 hours. So, 1.5 x 9 = 13.5 miles.
Each friend ran 2.25 miles (9 ÷ 4 = 2.25).
Simply add your times and divide by the distance (or visa-versa).21 minutes + 63 minutes = 84 minutes84 minutes/10 miles = 8.4 minute miles.Note, this is a convenient form to calculate speed for runners. However, the "standard" would be in MPH (or the metric equivalent).(10 miles / 84 minutes)*(60 minutes/hour) = 7.14 MPHA common fallacy might be to calculate the speed in each leg of the race and average.3 miles in 21 minutes = 7 minute miles.7 miles in 63 minutes = 9 minute miles.If you average these two you get 8 minute miles WHICH IS INCORRECT.The problem with this is that the runner ran each pace for different distances. If the distances at each pace were the same, then this would work.
9 mph
9 mins 14 secs per mile.
Jessiqa Pace is 5' 9".
17 min 9 seconds
It is 5 7/9 mph.