81w2 - p2 = (9w + p) (9w - p)because 81w2 - p2 is the difference of squares. To factor the difference of squares, square root both terms and write the binomial twice:(9w ? p) (9w ? p)Now, to replace the question marks, one binomial has to replace it with the plus sign, while the other binomial gets a minus sign:(9w + p) (9w - p)
(x - 16)(x + 2) x = 16 or -2
It is (A-1)(A+1) when factored
(7x + 8)(7x - 9)
(2x - 1)(4x + 1)
(9r - 8)(9r + 8)
It is: (c-4)(c-8) when factored
Remember to factor out the GCF of the coefficients if there is one. A perfect square binomial will always follow the pattern a squared plus or minus 2ab plus b squared. If it's plus 2ab, that factors to (a + b)(a + b) If it's minus 2ab, that factors to (a - b)(a - b)
3x squared minus 25x minus 28
There are no rational factors.
81w2 - p2 = (9w + p) (9w - p)because 81w2 - p2 is the difference of squares. To factor the difference of squares, square root both terms and write the binomial twice:(9w ? p) (9w ? p)Now, to replace the question marks, one binomial has to replace it with the plus sign, while the other binomial gets a minus sign:(9w + p) (9w - p)
(x - 16)(x + 2) x = 16 or -2
(a + 3)(a - 3)
(5x - 2y)(5x + 2y)
2x squared - 5x - 3 = (2x +1)(x -3)
Without that other number, all you've got is zero.
(x + 1)(x - 8)