It is: (c-4)(c-8) when factored
6(b - ac + b2 - bc)
(x - 1)(5x + 7)
(x-1)(x+2)
(4x - 3)(2x + 3)
Factor out the GCF and get X(X2-X+1).
Remember to factor out the GCF of the coefficients if there is one. A perfect square binomial will always follow the pattern a squared plus or minus 2ab plus b squared. If it's plus 2ab, that factors to (a + b)(a + b) If it's minus 2ab, that factors to (a - b)(a - b)
(x - 1)(3x + 5)
There are no rational factors.
There is no rational factorisation.
(b-c)(a+b)-ac
(a - 2)(a^2 + 6)
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
(3y - 5)(y + 5)
81w2 - p2 = (9w + p) (9w - p)because 81w2 - p2 is the difference of squares. To factor the difference of squares, square root both terms and write the binomial twice:(9w ? p) (9w ? p)Now, to replace the question marks, one binomial has to replace it with the plus sign, while the other binomial gets a minus sign:(9w + p) (9w - p)
(7a - 1)(6a + 1)
v2+36v+99 = (v+3)(v+33) when factored
(3r - 2)(3r - 2) or (3r - 2) squared.