6(b - ac + b2 - bc)
(4x - 3)(2x + 3)
(x-1)(x+2)
(x - 1)(5x + 7)
Factor out the GCF and get X(X2-X+1).
Remember to factor out the GCF of the coefficients if there is one. A perfect square binomial will always follow the pattern a squared plus or minus 2ab plus b squared. If it's plus 2ab, that factors to (a + b)(a + b) If it's minus 2ab, that factors to (a - b)(a - b)
(x - 1)(3x + 5)
There are no rational factors.
There is no rational factorisation.
(a - 2)(a^2 + 6)
(b-c)(a+b)-ac
(3y - 5)(y + 5)
(x + 3)(3x - 2)
81w2 - p2 = (9w + p) (9w - p)because 81w2 - p2 is the difference of squares. To factor the difference of squares, square root both terms and write the binomial twice:(9w ? p) (9w ? p)Now, to replace the question marks, one binomial has to replace it with the plus sign, while the other binomial gets a minus sign:(9w + p) (9w - p)
v2+36v+99 = (v+3)(v+33) when factored
(7a - 1)(6a + 1)
it is (x-y)(x-y) :)