The answer will depend on what x is.
2 X 22/7(pi) X Radius of the circle. You may use 3.14 as the value of pi.
A rectangle cannot really have the same area and perimeter because an area is a 2-dimensional concept while a perimeter is 1-dimensional.However, you can have rectangles such that the numericalvalue of their area and perimeter are the same.Take any number x > 2 and let y = 2x/(x-2)Then a rectangle with sides of x and y has an area and perimeter whose value is 2x2/(x-2)
You can't tell the perimeter from the area.Here are a few different rectangles and their perimeters.All of them enclose 12 square feet.1/2 x 24 .. . perimeter = 491 x 12 . . . . perimeter = 261.5 x 8 .. . . perimeter = 192 x 6 . . . . . perimeter = 162.4 x 5 .. . . perimeter = 14.83 x 4 . . . . . perimeter = 143.464 x 3.464 . . perimeter = 13.856
Assuming x is one of the sides of he rectangle, any value greater than zero and less than 71/2.
The answer will depend on what x is.
what is the value of x so that the perimeter of the rectangle shown is at least 92 centimeters
A+ =7
x=7 ft.
2 X 22/7(pi) X Radius of the circle. You may use 3.14 as the value of pi.
A rectangle cannot really have the same area and perimeter because an area is a 2-dimensional concept while a perimeter is 1-dimensional.However, you can have rectangles such that the numericalvalue of their area and perimeter are the same.Take any number x > 2 and let y = 2x/(x-2)Then a rectangle with sides of x and y has an area and perimeter whose value is 2x2/(x-2)
You can't tell the perimeter from the area.Here are a few different rectangles and their perimeters.All of them enclose 12 square feet.1/2 x 24 .. . perimeter = 491 x 12 . . . . perimeter = 261.5 x 8 .. . . perimeter = 192 x 6 . . . . . perimeter = 162.4 x 5 .. . . perimeter = 14.83 x 4 . . . . . perimeter = 143.464 x 3.464 . . perimeter = 13.856
Let's say the side length of a square is x. The square's area is just x2, and its perimeter is 4x. If we want the perimeter to be equal to the area, 4x = x2, so x = 4.
You cannot solve this equation without knowing the shape.
Assuming x is one of the sides of he rectangle, any value greater than zero and less than 71/2.
Since the perimeter is already known and there are no additional values of sides, nor is the shape known, one would mathematically say the x = 24 cm.
With great difficultly. The area could be any value greater than 0 units2 and less than or equal to the area of a square with the given perimeter which would be 1/16 x perimeter2 units2. To know which of the possible areas you would need to know the length of one side, then you can work out the area: perimeter = 2 x (length + width) ⇒ width = (1/2 x perimeter) - length ⇒ area = length x width = length x ((1/2 x perimeter) - length) = (1/2 x perimeter x length) - length2