That doesn't factor neatly. Applying the quadratic formula, we find two real solutions:-6 plus or minus 2 times the square root of 2
x = -3.1715728752538097
x = -8.82842712474619
-(x - 14)(x + 2)
(x + 4)(x + 8)
(x + 4)(x + 1)
x2-3x+2.25 is the same as 4x2-12x+9 and is (2x-3)(2x-3) when factored
(x + 13)(2 - x)
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
x2 + 12x + 27 = (x + 9)(x + 3)
-(x - 14)(x + 2)
x + 12x + 20 = (x + 10)(x + 2)
3x(x2 + 2x - 4)
-2x3 + 2x2 + 12x =(-2x) (x2 - x - 6) =(-2x) (x+2) (x-3)
I would do this. Multiply through by -1 -1 ( -X^2 +12X +28 ) = X^2 -12X -28 (X+2)(X-14)
(-2x3 - 2x2 + 12x) = -2x (x2 + x - 6) = -2x (x + 3) (x - 2)
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
x2-12x+36 = (x-6)2
x2 + 12x + 32 = (x + 8)(x + 4)
-2x3 + 2x2 + 12x = -2x(x2 - x - 6) = -2x(x2 + 2x - 3x - 6) = -2x[ x(x + 2) - 3(x + 2) ] = -2x(x - 3)(x + 2)