If that's - 338, the answer is 2(x + 13)(x - 13)
ax + ay - AZ = a(x + y - z)
(b + 2c)(b - c)
The other factor is 1.
12n2 plus 8n?
The grouping of the factors of w^2 + 30w + 81 (a perfect square) is (w + 27) and (w + 3)3 is a prime factor of 27, 30 and 81 but without two terms to compare, there won't be a GCF (not gfc)
You would factor 3a + 9b as: 3(a+3b)
4(y + 2)(y + 2)
4x3+12x2+3x+9
this problem cannot be factored
(6x + 1)(x + 13)
You didn't state what the problem is. Quite often you will want to either factor it, or solve the equation (in this case) 56x3 - 170x2 + 98x = 0. In this case, first take out the common factor "x". Then use the quadratic formula on what is left. (If, for example, 5 is a solution, then x - 5 is a factor.)
a(x + y - z)
(2a-3)(a-1)
If you mean "factors", the two monomials have the common factor x2. Divide each factor by x2 to get the other factor.
x2 + 12x + 32 = (x + 8)(x + 4)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
(2x - 9)(2x - 9)