If the polynomial is meant to be x2 + 19 + 10x + 19 then there is no real factorisation.
x2 + 19 + 10x + 19 = x2 + 10x + 38 has no real roots and so no real factorisation.
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This polynomial doesn't factor. The only thing you can do is take out parts of some terms, e.g. 2(2x3 + 10x2 + x) - 3.
(a + b)(r + s)
4d2+16 4(d2+4)
12n2 plus 8n?
(x + 9)(x + 4)
(x + 5) (x - 4)
x+11x+30(x+5)(x+6)
-2(2x^4 - 13x^3 + 15)
9xy2 - 24xy + 15x
n^2(n + 6)(n^2 - 6n + 36)
Factor the polynomial x2 - 10x + 25. Enter each factor as a polynomial in descending order.
(x + 8)(x + 1)
(3x + 4)(3x + 4)
(2x - 1)(2x + 3)
9x2 + 9x - 10 =(3x - 2)(3x + 5)
(x+1)(x+9)
(x-2)(x-3)