4x2+13x+3 m*n=(4*3)=12 m+n=13 m=12 n=1 (4x/12)=(x/3) (4x+1)(x+3)
13x^3
(x -3)(2x2 + 3x - 4)
There aren't any common factors, which makes the GCF 1. This is meaningless to factor out, since it leaves the original equation. If you meant to write -5x7, that makes the common factor -x2 and leaves (5x5 + 13)
if you mean x^2-36 1x^2+0x-36 a=1 b=0 c=-36 you can use quadratic formula (-b -+ sqrt (b^2-4ac))/2a you'll get (sqrt(144))/2= 6 and (-sqrt(144))/2= -6 as your two roots your answer (x+6)(x-6) or use inspection: what factors of c will give you b when added together if c=-36 and b=0. the roots 6 and -6 will get you 0 when added and -36 when multiplied. because 6 and -6 are your chosen factors the factored expression is (x+6)(x-6)
x2 + 13x + 36 = (x + 9)(x + 4)
It is (2x-5)(x-4) when factored
-2(2x^4 - 13x^3 + 15)
2x2+13x+15 = (2x+3)(x+5)
(x + 1)(3x + 10)
vbh
6x2 + 13x + 2 = (6x + 1)(x + 2).
3x2+13x-10 = (3x-2)(x+5) when factored
(x + 4)(x + 9)
(3x + 2)(2x + 3)
(x-4)
The expression cannot be factorised.