Factor x2 - 6x plus 8?

Answer 1

That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: -8 plus or minus i times the square root of 11.

x = -8 + 3.3166247903554i

x = -8 - 3.3166247903554i

where i is the imaginary square root of -1

Answer 2

This doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: Zero plus or minus 4i times the square root of 1

x = 4i, -4i

where i is the square root of -1.

Answer 3

x2 - 8x + 12

(x - 6)(x - 2)

x2 - 2x - 6x + 12

x2 - 8x + 12

x - 6 = 0

x = 6

x - 2 = 0

x = 2

Solution set: {2, 6}

Answer 4

It is not possible - you can't have two numbers that multiply to get one but add up to four

Answer 5

There is no factorisation with real roots. The complex roots are 8 +or- i*sqrt(11) where i is the imaginary square root of -1

Answer 6

(x - 2)(x - 2)(x2 + 2x + 4)

Answer 7

(x - 4)(x - 2)

Answer 8

(x + 7)(x + 5)

Answer 9

x-14

Answer 10

X((x+1)^2)