Given an undirected graph G=(V,E) and an integer k, find induced subgraph H=(U,F) of G of maximum size (maximum in terms of the number of vertices) such that all vertices of H have degree at least k
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Let G be a complete graph with n vertices. Consider the case where n=2. With only 2 vertices it is clear that there will only be one edge. Now add one more vertex to get n = 3. We must now add edges between the two old vertices and the new one for a total of 3 vertices. We see that adding a vertex to a graph with n vertices gives us n more edges. We get the following sequence Edges on a graph with n vertices: 0+1+2+3+4+5+...+n-1. Adding this to itself and dividing by two yields the following formula for the number of edges on a complete graph with n vertices: n(n-1)/2.
g => (g or h) => (s and t) => t => (t or u) => (c and d) => c.We are given premises:# (g or h) -> (s and t) # (t or u) -> (c and d) We would like to derive g -> c.If we assume g (the antecedent in the conclusion) we have the following derivation: # g (assumption) # g or h(weakening) # s and t (premise 1 (modus ponens)) # t(weakening) # t or u (weakening) # c and d (premise 2 (modus ponens)) # c (weakening)So, assuming g we can derive c, i.e. g -> c
G-20 Summit.^_^=
I found a website "textbook of basic nursing" that states pen-aqueous G antibiotics can be administered orally, IM & IV. However, it states Pen- G with procaine is IM only.
Here are some ideas: "No one knows what the G in his name stands for, neither does GIR himself." "GIR is a dysfunctional version of the Irken SIR (Standard-issue Information Retrieval unit) given to Irken invaders."