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Let G be a complete graph with n vertices. Consider the case where n=2. With only 2 vertices it is clear that there will only be one edge. Now add one more vertex to get n = 3. We must now add edges between the two old vertices and the new one for a total of 3 vertices. We see that adding a vertex to a graph with n vertices gives us n more edges. We get the following sequence

Edges on a graph with n vertices: 0+1+2+3+4+5+...+n-1. Adding this to itself and dividing by two yields the following formula for the number of edges on a complete graph with n vertices: n(n-1)/2.

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12y ago
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12y ago

(n-1)*(n-2)/2

That number would be achieved if all but one vertex were connected to every other vertex but that one remained isolated.

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11y ago

N*(N - 1)/2

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Q: What is the maximum number of distinct edges in an undirected graph with N vertices?
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