the definition of an angle bisector is a line that divides an angle into two equal halves. So you need only invoke the definition to prove something is an angle bisector if you already know that the two angles are congruent.
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The bisectors of the three angles of a triangle meet at a single point inside the triangle.
Similarities between angle bisector and perpendicular bisector: Perpendicular bisector bisects a line segment into two equal parts at 90°. Angle bisector bisects an creating two congruent angles they both bisect into equal parts! =)
The set of all points in a plane that are equidistant from the two sides of a given angle
Postulates are assumed to be true and we need not prove them. They provide the starting point for the proof of a theorem. A theorem is a proposition that can be deduced from postulates. We make a series of logical arguments using these postulates to prove a theorem. For example, visualize two angles, two parallel lines and a single slanted line through the parallel lines. Angle one, on the top, above the first parallel line is an obtuse angle. Angle two below the second parallel line is acute. These two angles are called Exterior angles. They are proved and is therefore a theorem.
If of triangle ABC and A'B'C' sides AB = A'B' and AC = A'C', and the included angle at A is larger than the included angle at A*, then BC > B'C'.Proof:A A'/|\ /|/ | \ / |/ | \ / |/ | \ B'/ |B | X \C |C'DWe construct AD such that AD = A'C' = AC and angle BAD = angle B'A'C'.Triangles ABD and A'B'C' are congruent. Therefore BD = B'C'.Let X be the point where the angle bisector of angle DAC meets BC.From the congruent triangles AXC and AXD (SAS) we have that XD = XC.Now, by the triangle inequality we have that BX + XD > BD, so BX + XC > BD, and consequently BC > BD = B'C'.
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