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Q: How do you factor 22y4-33y2 plus 11y?

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3x3

(4x + 1)(2x^2 + 3)

(x + 8)(x + 9)

(x + 18)(x + 4)

The GCF is 5.

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(y - 5)(y - 6)

(4y + 1)(3y + 2)

(4y + 1)(3y + 2)

11y(y - 1)(2y^2 + 2y - 1)

23y-11y = 12y

11y + 16 + 5y = 16y + 16 = 16(y + 1)

(5 - 11y - 12) + 8y = 5 - 11y - 12 + 8y = ( - 7 - 3y )

-2x -11y - 13

6y+5 = 11y+30 -25 = 5y -5 = y

11y

5x2+56xy+11y2 = (5x+y)(x+11y) when factored

6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y) 6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y) 6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y) 6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y)

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