(x + 11y)(x - 12y)
121y2 - 4 = (11y - 2)(11y + 2)
There is a formula for "the difference of squares." In this case, the answer is (6x + 11y)(6x - 11y)
The other factor is 1.
12n2 plus 8n?
(y - 5)(y - 6)
11y(y - 1)(2y^2 + 2y - 1)
(4y + 1)(3y + 2)
23y-11y = 12y
11y + 16 + 5y = 16y + 16 = 16(y + 1)
(5 - 11y - 12) + 8y = 5 - 11y - 12 + 8y = ( - 7 - 3y )
-2x -11y - 13
6y+5 = 11y+30 -25 = 5y -5 = y
5x2+56xy+11y2 = (5x+y)(x+11y) when factored
11y
6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y) 6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y) 6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y) 6x2+ 35xy + 11y2=6x2+ 33xy + 2xy + 11y2= 3x(2x + 11y) + y(2x + 11y)= (2x + 11y)*(3x + y)
6y2 + 11y - 2 = (6y - 1) (y + 2)