To factor the expression (6w - 15 - 14hw + 35h), first, rearrange it as (6w - 14hw + 35h - 15). Next, group the terms: (6w - 14hw + 35h) and (-15). Factor out common terms: from (6w - 14hw), factor out (2w) to get (2w(3 - 7h)), and from (35h - 15), factor out (5) to get (5(7h - 3)). Thus, the expression can be factored as (2w(3 - 7h) + 5(7h - 3)), which can be further simplified if necessary.
5(2g + 7h)
Yes, ( 5 \times 7h ) and ( 35h ) are equivalent. When you multiply ( 5 ) by ( 7h ), you get ( 35h ), which means both expressions represent the same value for any value of ( h ). Therefore, they are equivalent expressions.
The other factor is 1.
12n2 plus 8n?
(a + 2b)(c + 2d)
5(2g + 7h)
Yes 5*7h is the same as 35h
No because 35h is greater than 5h. 5 times h can be written as 5h.
Yes, ( 5 \times 7h ) and ( 35h ) are equivalent. When you multiply ( 5 ) by ( 7h ), you get ( 35h ), which means both expressions represent the same value for any value of ( h ). Therefore, they are equivalent expressions.
Yes.
equivalent
5m
The other factor is 1.
-7h = 35h = -5
(a + 2b)(a + 2b)
1h = 3600s 35h x 3600s/h = 126000s
factor the trinomial 16x^2+24x+9