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That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-1 plus or minus the square root of 265) divided by 12

x = 1.2732350496749756

x = -1.439901716341642

Q: What factor of 6x2 plus x1 - 11 in zeros of polynomial function?

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This polynomial doesn't factor. The only thing you can do is take out parts of some terms, e.g. 2(2x3 + 10x2 + x) - 3.

(a + b)(r + s)

4d2+16 4(d2+4)

Take out the common factor, 3: 3x + 6 = 3(x + 2).

That doesn't factor neatly. Applying the quadratic formula, we find 2 imaginary solutions: (-1 plus or minus the square root of -83) divided by 2x = -0.5 + 4.55521678957215ix = -0.5 - 4.55521678957215iwhere i is the square root of -1.

Related questions

They are x = 0, -5 and +8.

Factor the polynomial x2 - 10x + 25. Enter each factor as a polynomial in descending order.

(x + 8)(x + 1)

(3x + 4)(3x + 4)

(x+1)(x+9)

(x-2)(x-3)

(x-3)(x+8)

(x - 3)(x - 3)

(x + 8)(x + 1)

(x-4) (x+7)

2x+5x-24 7x2-24

The only factor is 2. 2*(t3 + 2t2 + 4x)