That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-1 plus or minus the square root of 265) divided by 12
x = 1.2732350496749756
x = -1.439901716341642
This polynomial doesn't factor. The only thing you can do is take out parts of some terms, e.g. 2(2x3 + 10x2 + x) - 3.
(a + b)(r + s)
4d2+16 4(d2+4)
Take out the common factor, 3: 3x + 6 = 3(x + 2).
That doesn't factor neatly. Applying the quadratic formula, we find 2 imaginary solutions: (-1 plus or minus the square root of -83) divided by 2x = -0.5 + 4.55521678957215ix = -0.5 - 4.55521678957215iwhere i is the square root of -1.
The function ( f(x) = x^2 - 6x + 8 ) is a polynomial function because it is a quadratic expression. To find the zeros, we can factor it as ( (x - 2)(x - 4) ), which gives us the zeros ( x = 2 ) and ( x = 4 ). Thus, the zeros of the function are 2 and 4.
They are x = 0, -5 and +8.
Factor the polynomial x2 - 10x + 25. Enter each factor as a polynomial in descending order.
(x + 8)(x + 1)
(3x + 4)(3x + 4)
(x+1)(x+9)
(x-3)(x+8)
(x - 3)(x - 3)
(x-2)(x-3)
(x + 8)(x + 1)
2x+5x-24 7x2-24
(x-4) (x+7)